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分布計(jì)算,分布計(jì)算36除以3與3的積商是多少這道題怎么做分布計(jì)算

來(lái)源:整理 時(shí)間:2023-10-17 12:34:56 編輯:智能門(mén)戶 手機(jī)版

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1,分布計(jì)算36除以3與3的積商是多少這道題怎么做分布計(jì)算

36/3*3=36/9=4
(880-36x15)÷17=20

分布計(jì)算36除以3與3的積商是多少這道題怎么做分布計(jì)算

2,正態(tài)分布常用公式

你這里a>0,所以P因?yàn)镻{|x|≥a}=P{x≥a}+P{x≤-a},標(biāo)準(zhǔn)正態(tài)分布P{x≥a}=P{x≤-a},所以P{x≥a}=P{|x|≥a}/2
自然對(duì)數(shù)的底,是(1+1/n)^n在n趨向正無(wú)窮時(shí)的極限,其值約等于2.718281828。計(jì)算的時(shí)候直接代入就行了。一般數(shù)學(xué)軟件里面都可以直接用。 至于為什么正態(tài)分布公式里會(huì)有e存在,我想是在計(jì)算分布的時(shí)候總體越大越精確,所以會(huì)取一個(gè)n趨向正無(wú)窮的數(shù),那么出現(xiàn)了上面的極限,就用e來(lái)代替了。

正態(tài)分布常用公式

3,怎么用科學(xué)計(jì)算器 算正態(tài)分布值

計(jì)算方法:(1) P(Z≥0.3)=0.3821 a 進(jìn)入單一變量統(tǒng)計(jì)模b 進(jìn)入正態(tài)分布模式 shift 1 7 3 0.3 ) =(2) p(-0.3≤Z≤0.3)=0.2358 a 進(jìn)入單一變量統(tǒng)計(jì)模式 Mode 3 1 AC b 進(jìn)入正態(tài)分布模式 shift 1 7 3 0.3 ) - shift 1 7 3 (-)0.3 )=
計(jì)算方法:(1)p(z≥0.3)a進(jìn)入單一變量統(tǒng)計(jì)模式mode31acb進(jìn)入正態(tài)分布模式shift1730.3)=(2)p(-0.3≤z≤0.3)=0.2358a進(jìn)入單一變量統(tǒng)計(jì)模式mode31acb進(jìn)入正態(tài)分布模式shift1730.3)-shift173(-)0.3)=

怎么用科學(xué)計(jì)算器 算正態(tài)分布值

4,如何使用韋伯分布函數(shù)

weibull(x,alpha,beta,cumulative)x 參數(shù)值。alpha 分布參數(shù)。beta 分布參數(shù)。cumulative 指明函數(shù)的形式。說(shuō)明如果x、alpha 或 beta 為非數(shù)值型,函數(shù) weibull 返回錯(cuò)誤值 #value!。 如果x < 0,函數(shù) weibull 返回錯(cuò)誤值 #num!。 如果alpha ≤ 0 或 beta ≤ 0,函數(shù) weibull 返回錯(cuò)誤值 #num!。 韋伯累積分布函數(shù)的計(jì)算公式如下: 韋伯概率密度函數(shù)的計(jì)算公式如下: 當(dāng)alpha = 1,函數(shù) weibull 返回指數(shù)分布: 示例如果您將示例復(fù)制到空白工作表中,可能會(huì)更易于理解該示例。操作方法創(chuàng)建空白工作簿或工作表。 請(qǐng)?jiān)凇皫椭敝黝}中選取示例。不要選取行或列標(biāo)題。 從幫助中選取示例。 按ctrl+c。 在工作表中,選中單元格 a1,再按 ctrl+v。 若要在查看結(jié)果和查看返回結(jié)果的公式之間切換,請(qǐng)按 ctrl+`(重音符),或在“工具”菜單上,指向“公式審核”,再單擊“公式審核模式”。 1234ab數(shù)據(jù)說(shuō)明105計(jì)算函數(shù)的數(shù)值20α 分布參數(shù)100β 分布參數(shù)公式說(shuō)明(結(jié)果)=weibull(a2,a3,a4,true)在上述條件下使用韋伯累積分布函數(shù)的結(jié)果 (0.929581)=weibull(a2,a3,a4,false)在上述條件下使用韋伯概率密度函數(shù)的結(jié)果 (0.035589)
密度函數(shù): x≤0時(shí),p(x)=0; x﹥0時(shí),p(x)=aλx^(a-1)exp(-λx^a). 累計(jì)分布函數(shù): x≤0時(shí),F(xiàn)(x)=0; x>0時(shí),F(xiàn)(x)=∫aλt^(a-1)exp(-λt^a)dt 積分(0,x) =-∫exp(-λt^a)d(-λt^a) =- exp(-λt^a) t從0到x =1- exp(-λx^a) 結(jié)論:x≤0時(shí),F(xiàn)(x)=0; x>0時(shí),F(xiàn)(x)=1- exp(-λx^a)

5,如何求概率分布

求出概率分布函數(shù)然后在整個(gè)區(qū)間上積分
好,我試著描述了一下從1 -5 的分布幾率 以及變化:in 1d6 case, the result is as following:the probability of getting a 1 is 0.17the probability of getting a 2 is 0.17the probability of getting a 3 is 0.17the probability of getting a 4 is 0.17the probability of getting a 5 is 0.17the probability of getting a 6 is 0.17in 2d6 case, the result is as following:the probability of getting a 2 is 0.03the probability of getting a 3 is 0.06the probability of getting a 4 is 0.08the probability of getting a 5 is 0.11the probability of getting a 6 is 0.14the probability of getting a 7 is 0.17the probability of getting a 8 is 0.14the probability of getting a 9 is 0.11the probability of getting a 10 is 0.08the probability of getting a 11 is 0.06the probability of getting a 12 is 0.03in 3d6 case, the result is as following:the probability of getting a 3 is 0.00the probability of getting a 4 is 0.01the probability of getting a 5 is 0.03the probability of getting a 6 is 0.05the probability of getting a 7 is 0.07the probability of getting a 8 is 0.10the probability of getting a 9 is 0.12the probability of getting a 10 is 0.12the probability of getting a 11 is 0.13the probability of getting a 12 is 0.12the probability of getting a 13 is 0.10the probability of getting a 14 is 0.07the probability of getting a 15 is 0.05the probability of getting a 16 is 0.03the probability of getting a 17 is 0.01the probability of getting a 18 is 0.00in 4d6 case, the result is as following:the probability of getting a 4 is 0.00the probability of getting a 5 is 0.00the probability of getting a 6 is 0.01the probability of getting a 7 is 0.02the probability of getting a 8 is 0.03the probability of getting a 9 is 0.04the probability of getting a 10 is 0.06the probability of getting a 11 is 0.08the probability of getting a 12 is 0.10the probability of getting a 13 is 0.11the probability of getting a 14 is 0.11the probability of getting a 15 is 0.11the probability of getting a 16 is 0.10the probability of getting a 17 is 0.08the probability of getting a 18 is 0.06the probability of getting a 19 is 0.04the probability of getting a 20 is 0.03the probability of getting a 21 is 0.02the probability of getting a 22 is 0.01the probability of getting a 23 is 0.00the probability of getting a 24 is 0.00in 5d6 case, the result is as following:the probability of getting a 5 is 0.00the probability of getting a 6 is 0.00the probability of getting a 7 is 0.00the probability of getting a 8 is 0.00the probability of getting a 9 is 0.01the probability of getting a 10 is 0.02the probability of getting a 11 is 0.03the probability of getting a 12 is 0.04the probability of getting a 13 is 0.05the probability of getting a 14 is 0.07the probability of getting a 15 is 0.08the probability of getting a 16 is 0.09the probability of getting a 17 is 0.10the probability of getting a 18 is 0.10the probability of getting a 19 is 0.09the probability of getting a 20 is 0.08the probability of getting a 21 is 0.07the probability of getting a 22 is 0.05the probability of getting a 23 is 0.04the probability of getting a 24 is 0.03the probability of getting a 25 is 0.02the probability of getting a 26 is 0.01the probability of getting a 27 is 0.00the probability of getting a 28 is 0.00the probability of getting a 29 is 0.00the probability of getting a 30 is 0.006d6上面的東西都和武器無(wú)緣了。。。不是長(zhǎng)期擁有的東西也沒(méi)必要去在意它到底出多少點(diǎn)吧? 大概規(guī)律就是中間多兩邊少,成鐘型分布。下面是程序:/* * to change this template, choose tools | templates * and open the template in the editor. */package diceandprobability;import java.text.decimalformat;import java.text.numberformat;import java.util.arraylist;import java.util.iterator;import java.util.list;import java.util.random;/** * * @author yichuan */public class main /** * @param args the command line arguments */ public static void main(string[] args) final int total_roll = 1000000; final int num_dice = 2; final string prompt = "in " + num_dice + "d6 case, the result is as following:\n"; random ran = new random(); list result = new arraylist(); int num = 0; int count = 0; for(int i = 0; i < total_roll; i++){ for(int j = 0; j < num_dice; j ++){ num += ran.nextint(6)+1; } result.add(num); num = 0; } system.out.println(prompt); for(int i = num_dice; i <= num_dice * 6; i ++){ iterator iter = result.iterator(); while(iter.hasnext()){ if (iter.next() == i){ count ++; } } double amount = count / (total_roll + 0.0); numberformat format = new decimalformat("#0.00000"); system.out.println("the probability of getting a " + i + " is " + format.format(amount)); count = 0; } } }

6,求概率分布

題很簡(jiǎn)單,描述很麻煩。直接給結(jié)果自己看看。概率分布:pEX=3x1/20+4x3/20+5x6/20+6x10/20=21/4DX=(3-ex)^2+(4-ex)^2...=嘿嘿,自己算了哈!哥也要考概率了,加油哈!
好,我試著描述了一下從1 -5 的分布幾率 以及變化:in 1d6 case, the result is as following:the probability of getting a 1 is 0.17the probability of getting a 2 is 0.17the probability of getting a 3 is 0.17the probability of getting a 4 is 0.17the probability of getting a 5 is 0.17the probability of getting a 6 is 0.17in 2d6 case, the result is as following:the probability of getting a 2 is 0.03the probability of getting a 3 is 0.06the probability of getting a 4 is 0.08the probability of getting a 5 is 0.11the probability of getting a 6 is 0.14the probability of getting a 7 is 0.17the probability of getting a 8 is 0.14the probability of getting a 9 is 0.11the probability of getting a 10 is 0.08the probability of getting a 11 is 0.06the probability of getting a 12 is 0.03in 3d6 case, the result is as following:the probability of getting a 3 is 0.00the probability of getting a 4 is 0.01the probability of getting a 5 is 0.03the probability of getting a 6 is 0.05the probability of getting a 7 is 0.07the probability of getting a 8 is 0.10the probability of getting a 9 is 0.12the probability of getting a 10 is 0.12the probability of getting a 11 is 0.13the probability of getting a 12 is 0.12the probability of getting a 13 is 0.10the probability of getting a 14 is 0.07the probability of getting a 15 is 0.05the probability of getting a 16 is 0.03the probability of getting a 17 is 0.01the probability of getting a 18 is 0.00in 4d6 case, the result is as following:the probability of getting a 4 is 0.00the probability of getting a 5 is 0.00the probability of getting a 6 is 0.01the probability of getting a 7 is 0.02the probability of getting a 8 is 0.03the probability of getting a 9 is 0.04the probability of getting a 10 is 0.06the probability of getting a 11 is 0.08the probability of getting a 12 is 0.10the probability of getting a 13 is 0.11the probability of getting a 14 is 0.11the probability of getting a 15 is 0.11the probability of getting a 16 is 0.10the probability of getting a 17 is 0.08the probability of getting a 18 is 0.06the probability of getting a 19 is 0.04the probability of getting a 20 is 0.03the probability of getting a 21 is 0.02the probability of getting a 22 is 0.01the probability of getting a 23 is 0.00the probability of getting a 24 is 0.00in 5d6 case, the result is as following:the probability of getting a 5 is 0.00the probability of getting a 6 is 0.00the probability of getting a 7 is 0.00the probability of getting a 8 is 0.00the probability of getting a 9 is 0.01the probability of getting a 10 is 0.02the probability of getting a 11 is 0.03the probability of getting a 12 is 0.04the probability of getting a 13 is 0.05the probability of getting a 14 is 0.07the probability of getting a 15 is 0.08the probability of getting a 16 is 0.09the probability of getting a 17 is 0.10the probability of getting a 18 is 0.10the probability of getting a 19 is 0.09the probability of getting a 20 is 0.08the probability of getting a 21 is 0.07the probability of getting a 22 is 0.05the probability of getting a 23 is 0.04the probability of getting a 24 is 0.03the probability of getting a 25 is 0.02the probability of getting a 26 is 0.01the probability of getting a 27 is 0.00the probability of getting a 28 is 0.00the probability of getting a 29 is 0.00the probability of getting a 30 is 0.006d6上面的東西都和武器無(wú)緣了。。。不是長(zhǎng)期擁有的東西也沒(méi)必要去在意它到底出多少點(diǎn)吧? 大概規(guī)律就是中間多兩邊少,成鐘型分布。下面是程序:/* * to change this template, choose tools | templates * and open the template in the editor. */package diceandprobability;import java.text.decimalformat;import java.text.numberformat;import java.util.arraylist;import java.util.iterator;import java.util.list;import java.util.random;/** * * @author yichuan */public class main /** * @param args the command line arguments */ public static void main(string[] args) final int total_roll = 1000000; final int num_dice = 2; final string prompt = "in " + num_dice + "d6 case, the result is as following:\n"; random ran = new random(); list result = new arraylist(); int num = 0; int count = 0; for(int i = 0; i < total_roll; i++){ for(int j = 0; j < num_dice; j ++){ num += ran.nextint(6)+1; } result.add(num); num = 0; } system.out.println(prompt); for(int i = num_dice; i <= num_dice * 6; i ++){ iterator iter = result.iterator(); while(iter.hasnext()){ if (iter.next() == i){ count ++; } } double amount = count / (total_roll + 0.0); numberformat format = new decimalformat("#0.00000"); system.out.println("the probability of getting a " + i + " is " + format.format(amount)); count = 0; } } }
文章TAG:分布分布計(jì)算計(jì)算除以分布計(jì)算

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