分布計算，分布計算36除以3與3的積商是多少這道題怎么做分布計算

來源：整理時間：2023-10-17 12:34:56 編輯：智能門戶手機版

本文目錄一覽

1，分布計算36除以3與3的積商是多少這道題怎么做分布計算
2，正態(tài)分布常用公式
3，怎么用科學(xué)計算器算正態(tài)分布值
4，如何使用韋伯分布函數(shù)
5，如何求概率分布
6，求概率分布

1，分布計算36除以3與3的積商是多少這道題怎么做分布計算

36/3*3=36/9=4

（880-36x15）÷17=20

分布計算36除以3與3的積商是多少這道題怎么做分布計算

2，正態(tài)分布常用公式

你這里a>0，所以P因為P{|x|≥a}=P{x≥a}+P{x≤-a}，標(biāo)準(zhǔn)正態(tài)分布P{x≥a}=P{x≤-a}，所以P{x≥a}=P{|x|≥a}/2

自然對數(shù)的底，是（1+1/n）^n在n趨向正無窮時的極限，其值約等于2.718281828。計算的時候直接代入就行了。一般數(shù)學(xué)軟件里面都可以直接用。至于為什么正態(tài)分布公式里會有e存在，我想是在計算分布的時候總體越大越精確，所以會取一個n趨向正無窮的數(shù)，那么出現(xiàn)了上面的極限，就用e來代替了。

正態(tài)分布常用公式

3，怎么用科學(xué)計算器算正態(tài)分布值

計算方法：(1) P（Z≥0.3）=0.3821 a 進入單一變量統(tǒng)計模b 進入正態(tài)分布模式 shift 1 7 3 0.3 ） =(2) p(－0.3≤Z≤0.3)=0.2358 a 進入單一變量統(tǒng)計模式 Mode 3 1 AC b 進入正態(tài)分布模式 shift 1 7 3 0.3 ）－ shift 1 7 3 （－）0.3 ）=

計算方法：(1)p（z≥0.3）a進入單一變量統(tǒng)計模式mode31acb進入正態(tài)分布模式shift1730.3）=(2)p(－0.3≤z≤0.3)=0.2358a進入單一變量統(tǒng)計模式mode31acb進入正態(tài)分布模式shift1730.3）－shift173（－）0.3）=

怎么用科學(xué)計算器算正態(tài)分布值

4，如何使用韋伯分布函數(shù)

weibull(x,alpha,beta,cumulative)x 參數(shù)值。alpha 分布參數(shù)。beta 分布參數(shù)。cumulative 指明函數(shù)的形式。說明如果x、alpha 或 beta 為非數(shù)值型，函數(shù) weibull 返回錯誤值 #value!。如果x < 0，函數(shù) weibull 返回錯誤值 #num!。如果alpha ≤ 0 或 beta ≤ 0，函數(shù) weibull 返回錯誤值 #num!。韋伯累積分布函數(shù)的計算公式如下：韋伯概率密度函數(shù)的計算公式如下：當(dāng)alpha = 1，函數(shù) weibull 返回指數(shù)分布：示例如果您將示例復(fù)制到空白工作表中，可能會更易于理解該示例。操作方法創(chuàng)建空白工作簿或工作表。請在“幫助”主題中選取示例。不要選取行或列標(biāo)題。從幫助中選取示例。按ctrl+c。在工作表中，選中單元格 a1，再按 ctrl+v。若要在查看結(jié)果和查看返回結(jié)果的公式之間切換，請按 ctrl+`（重音符），或在“工具”菜單上，指向“公式審核”，再單擊“公式審核模式”。 1234ab數(shù)據(jù)說明105計算函數(shù)的數(shù)值20α 分布參數(shù)100β 分布參數(shù)公式說明（結(jié)果）=weibull(a2,a3,a4,true)在上述條件下使用韋伯累積分布函數(shù)的結(jié)果 (0.929581)=weibull(a2,a3,a4,false)在上述條件下使用韋伯概率密度函數(shù)的結(jié)果 (0.035589)

密度函數(shù)： x≤0時，p(x)=0; x﹥0時，p(x)=aλx^(a-1)exp(-λx^a). 累計分布函數(shù)： x≤0時，F(xiàn)(x)=0； x＞0時，F(xiàn)(x)=∫aλt^(a-1)exp(-λt^a)dt 積分(0,x) =-∫exp(-λt^a)d(-λt^a) =- exp(-λt^a) t從0到x =1- exp(-λx^a) 結(jié)論：x≤0時，F(xiàn)(x)=0； x＞0時，F(xiàn)(x)=1- exp(-λx^a)

5，如何求概率分布

求出概率分布函數(shù)然后在整個區(qū)間上積分

好，我試著描述了一下從1 -5 的分布幾率以及變化:in 1d6 case, the result is as following:the probability of getting a 1 is 0.17the probability of getting a 2 is 0.17the probability of getting a 3 is 0.17the probability of getting a 4 is 0.17the probability of getting a 5 is 0.17the probability of getting a 6 is 0.17in 2d6 case, the result is as following:the probability of getting a 2 is 0.03the probability of getting a 3 is 0.06the probability of getting a 4 is 0.08the probability of getting a 5 is 0.11the probability of getting a 6 is 0.14the probability of getting a 7 is 0.17the probability of getting a 8 is 0.14the probability of getting a 9 is 0.11the probability of getting a 10 is 0.08the probability of getting a 11 is 0.06the probability of getting a 12 is 0.03in 3d6 case, the result is as following:the probability of getting a 3 is 0.00the probability of getting a 4 is 0.01the probability of getting a 5 is 0.03the probability of getting a 6 is 0.05the probability of getting a 7 is 0.07the probability of getting a 8 is 0.10the probability of getting a 9 is 0.12the probability of getting a 10 is 0.12the probability of getting a 11 is 0.13the probability of getting a 12 is 0.12the probability of getting a 13 is 0.10the probability of getting a 14 is 0.07the probability of getting a 15 is 0.05the probability of getting a 16 is 0.03the probability of getting a 17 is 0.01the probability of getting a 18 is 0.00in 4d6 case, the result is as following:the probability of getting a 4 is 0.00the probability of getting a 5 is 0.00the probability of getting a 6 is 0.01the probability of getting a 7 is 0.02the probability of getting a 8 is 0.03the probability of getting a 9 is 0.04the probability of getting a 10 is 0.06the probability of getting a 11 is 0.08the probability of getting a 12 is 0.10the probability of getting a 13 is 0.11the probability of getting a 14 is 0.11the probability of getting a 15 is 0.11the probability of getting a 16 is 0.10the probability of getting a 17 is 0.08the probability of getting a 18 is 0.06the probability of getting a 19 is 0.04the probability of getting a 20 is 0.03the probability of getting a 21 is 0.02the probability of getting a 22 is 0.01the probability of getting a 23 is 0.00the probability of getting a 24 is 0.00in 5d6 case, the result is as following:the probability of getting a 5 is 0.00the probability of getting a 6 is 0.00the probability of getting a 7 is 0.00the probability of getting a 8 is 0.00the probability of getting a 9 is 0.01the probability of getting a 10 is 0.02the probability of getting a 11 is 0.03the probability of getting a 12 is 0.04the probability of getting a 13 is 0.05the probability of getting a 14 is 0.07the probability of getting a 15 is 0.08the probability of getting a 16 is 0.09the probability of getting a 17 is 0.10the probability of getting a 18 is 0.10the probability of getting a 19 is 0.09the probability of getting a 20 is 0.08the probability of getting a 21 is 0.07the probability of getting a 22 is 0.05the probability of getting a 23 is 0.04the probability of getting a 24 is 0.03the probability of getting a 25 is 0.02the probability of getting a 26 is 0.01the probability of getting a 27 is 0.00the probability of getting a 28 is 0.00the probability of getting a 29 is 0.00the probability of getting a 30 is 0.006d6上面的東西都和武器無緣了。。。不是長期擁有的東西也沒必要去在意它到底出多少點吧？大概規(guī)律就是中間多兩邊少，成鐘型分布。下面是程序：/* * to change this template, choose tools | templates * and open the template in the editor. */package diceandprobability;import java.text.decimalformat;import java.text.numberformat;import java.util.arraylist;import java.util.iterator;import java.util.list;import java.util.random;/** * * @author yichuan */public class main /** * @param args the command line arguments */ public static void main(string[] args) final int total_roll = 1000000; final int num_dice = 2; final string prompt = "in " + num_dice + "d6 case, the result is as following:\n"; random ran = new random(); list result = new arraylist(); int num = 0; int count = 0; for(int i = 0; i < total_roll; i++){ for(int j = 0; j < num_dice; j ++){ num += ran.nextint(6)+1; } result.add(num); num = 0; } system.out.println(prompt); for(int i = num_dice; i <= num_dice * 6; i ++){ iterator iter = result.iterator(); while(iter.hasnext()){ if (iter.next() == i){ count ++; } } double amount = count / (total_roll + 0.0); numberformat format = new decimalformat("#0.00000"); system.out.println("the probability of getting a " + i + " is " + format.format(amount)); count = 0; } } }

6，求概率分布

題很簡單，描述很麻煩。直接給結(jié)果自己看看。概率分布:pEX=3x1/20+4x3/20+5x6/20+6x10/20=21/4DX=(3-ex)^2+(4-ex)^2...=嘿嘿，自己算了哈!哥也要考概率了，加油哈!

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分布計算，分布計算36除以3與3的積商是多少這道題怎么做分布計算

本文目錄一覽

1，分布計算36除以3與3的積商是多少這道題怎么做分布計算

2，正態(tài)分布常用公式

3，怎么用科學(xué)計算器算正態(tài)分布值

4，如何使用韋伯分布函數(shù)

5，如何求概率分布

6，求概率分布

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分布計算，分布計算36除以3與3的積商是多少這道題怎么做分布計算

本文目錄一覽

1，分布計算36除以3與3的積商是多少這道題怎么做分布計算

2，正態(tài)分布常用公式

3，怎么用科學(xué)計算器 算正態(tài)分布值

4，如何使用韋伯分布函數(shù)

5，如何求概率分布

6，求概率分布

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經(jīng)驗最新文章

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分布計算，分布計算36除以3與3的積商是多少這道題怎么做分布計算

1，分布計算36除以3與3的積商是多少這道題怎么做分布計算

2，正態(tài)分布常用公式

3，怎么用科學(xué)計算器算正態(tài)分布值

4，如何使用韋伯分布函數(shù)

5，如何求概率分布

6，求概率分布